3y^2+4y+1/9y^2-1

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Solution for 3y^2+4y+1/9y^2-1 equation: 


y in (-oo:+oo)

3*y^2+(1/9)*y^2+4*y-1 = 0

28/9*y^2+4*y-1 = 0

DELTA = 4^2-(-1*28/9*4)

DELTA = 256/9

DELTA > 0

y = ((256/9)^(1/2)-4)/(2*28/9) or y = (-(256/9)^(1/2)-4)/(2*28/9)

y = 3/14 or y = -3/2

y in { -3/2, 3/14 }

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